Protons are projected at an angle of 30degrees with an initial speed, given by Vo=8.2*10^5 m/s, in a region of an electric field E=-390j N/C, is present. The proton is to hit a point 1.27 mm in the pos-x direction from the launch point. Find (a) the two porjections angles (theta) that will result in a hit, and (b) the total time of flight for each of these two trajectories.
Here is what I can get for this one, but i can't take it any farther.
(theta)=cos^-1(Vox/Vo)
(theta)=sin^-1(Voy/Vo)
F=q*E=-1.15*10^-16 N
a=F/m=-6.89*10^10 m/s^2
What angle to hit at a certain distance
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Quote:Protons are projected at an angle of 30degrees with an initial speed, given by Vo=8.2*10^5 m/s, in a region of an electric field E=-390j N/C, is present. The proton is to hit a point 1.27 mm in the pos-x direction from the launch point. Find (a) the two porjections angles (theta) that will result in a hit, and (b) the total time of flight for each of these two trajectories.
Here is what I can get for this one, but i can't take it any farther.
(theta)=cos^-1(Vox/Vo)
(theta)=sin^-1(Voy/Vo)
F=q*E=-1.15*10^-16 N
a=F/m=-6.89*10^10 m/s^2
Solution
To Find the angles you have written the formulas which can be used, just put the values of Vox and Voy as the horizontal and vertical components of the velocity and v and given in the question
Hoizontal componets would be given by vCos30 and Vertical by vSin30
This would give you two angles
For finding time of flight you have to use the basic equation of motion
S=ut+(at^2)/2
Use distance as required and put the values of acceleration.
Use only the velcoity in x direction as we have to move object in x direction target
Hope this helps
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