This is problem #83 on the 1998 AP Calculus test. How is this solved?
The Taylor series for ln(x), centered at x=1, is sigma((-1)^(n+1) * (x-1)^n/n) for n goes from 1 to infinity. Let f be the function given by the sum of the first three nonzero terms of this series.
Find the maximum value of abs(lnx - f(x)).
(The answer is given to be 0.145)
Taylor Series
Sorry, but I forgot to give the interval.
The interval for x is [.3,1.7]
I can do this by graphing the two functions and finding the maximum difference.
I was looking for an analytical method.