A 400.0-N child and a 300.0-N child sit on either end of a 2.00-m-long seesaw. where along the seesaw should the pivot support be placed to ensure rotational equilibrium? (the center of gravity is at the geometric center of the object)

Let it be placed at distance x from 400 N

400x=300(2-x)
400x=600-300x

700x=600
x=6/7

Now can you find the other distance

What is the equation on solving rotation equilbrium. This is the problem that I'm trying to solve:
A 400.0-N child and a 300.0-N child sit on either end of a 2.00-m-long seesaw. where along the seesaw should the pivot support be placed to ensure rotational equilibrium? (the center of gravity is at the geometric center of the object)

Matt

Hello Shiloh

1 feet = 1/3 meters

Just divide by 3 to chance it to meter/ second

Hope this helps
With Regards
Jamie